Answer:
It's very simple. In 4 decimal digits there are 10,000 (0000 to 9999) possible values. The odds of any one of them coming up randomly is one in 10,000. A specific "4 digit number" would have 1/9000 chance, since there are 9000 4 digit numbers (1000-9999).
Step-by-step explanation:
Answer:
2,4,6,1,3
Step-by-step explanation:
Answer: 40
Step-by-step explanation:
I can see the answer is 40, but let's try to figure out how to do it.
I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

''x'' represents the number of passes in 15 games.
Solve for x;
