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Sveta_85 [38]
2 years ago
10

Solve the quadratic equation graphically using at least two different approaches. When necessary, give your solutions to the nea

rest hundredth.
16x^2-400=0
Mathematics
1 answer:
Misha Larkins [42]2 years ago
5 0
The answer to the problem is 39

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Answer to be named brainliset get 25 pts and get a thank you
lisabon 2012 [21]

Answer:

The scale factor is .625 is false The scale factor 1.6 is true

Step-by-step explanation:

Since the triangle gets bigger the multiplication factor needs to be more than one to make the end result bigger

4 0
2 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
3/5 of an apple tree is unripe what percent of it is ripe?
trapecia [35]
If 3/5 of the tree is unripe, then 2/5 of the tree is ripe.

2/5 = 0.4

0.4 x 100 = 40% of the tree is ripe
4 0
3 years ago
Read 2 more answers
Please Help!<br> Order these from least to greatest.<br><br> 6.23, -√38, -19/3, -6.5555555...
Tanya [424]
Lol i dont know the answer but i love your profile pic again sorry 
5 0
3 years ago
Read 2 more answers
What are the midline, amplitude, and period of the graphed sine function?
Sunny_sXe [5.5K]

The midline, amplitude and period respectively of the given sine graph are; x = 1; 2; π

<h3>Midline, Amplitude and Period</h3>

The midline of this trigonometric graph is defined as the horizontal line that divides the maximum and minimum point distance into two equal parts. In this case, the midline is x = 1

The amplitude of a graphed function is usually the peak of the wave of that graph. In this case, we see that the peak of the graph is at y = 4. Thus, Amplitude = 4

Period is the difference between two consecutive maximum or minimum points. In this graph, the period is π

Read more about Midline, Amplitude and Period at; brainly.com/question/21124447

7 0
2 years ago
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