A=2...
Subtract 14 from both sides,then subtract 8 from both sides. Your left with
6a=12
6x1=6
6x2=12
A=2
Step-by-step explanation:
<em>2</em><em>+</em><em>1</em><em>9</em><em>=</em><em>7x</em>
<em>2</em><em>1</em><em>=</em><em>7x</em>
<em>21</em><em>÷</em><em>7</em><em>=</em><em>7x</em><em>÷</em><em>7</em>
<em>3</em><em>=</em><em>x</em>
<em>.</em><em>.</em>
For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:
The given line is:
So we have:
We find 
So, a line perpendicular to the one given is of the form:
We substitute the given point to find "b":
Finally we have:
In point-slope form we have:
ANswer:
Answer:
x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 12 x - 23 = -5
Divide both sides by 8:
x^2 - (3 x)/2 - 23/8 = -5/8
Add 23/8 to both sides:
x^2 - (3 x)/2 = 9/4
Add 9/16 to both sides:
x^2 - (3 x)/2 + 9/16 = 45/16
Write the left hand side as a square:
(x - 3/4)^2 = 45/16
Take the square root of both sides:
x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4
Add 3/4 to both sides:
Answer: x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4
The slope of the line between the points On the line would be -1. And the y intercept would be 1.
Y = -x + 1.
