Question

How to write y= 2x^2 + 8x +7 in standard (vertex) form

Answer 1

$2x^2+8x+7= \\ 2(x^2+4x)+7= \\ 2(x^2+4x+4-4)+7= \\ 2((x+2)^2-4)+7= \\ 2(x+2)^2-8+7= \\ 2(x+2)^2-1 \\ \\ \boxed{y=2(x+2)^2-1}$