3 years ago

How to write y= 2x^2 + 8x +7 in standard (vertex) form

1 answer:

3 0

$2x^2+8x+7= \\
2(x^2+4x)+7= \\
2(x^2+4x+4-4)+7= \\
2((x+2)^2-4)+7= \\
2(x+2)^2-8+7= \\
2(x+2)^2-1 \\ \\
\boxed{y=2(x+2)^2-1}$

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