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salantis [7]
3 years ago
11

How to write y= 2x^2 + 8x +7 in standard (vertex) form

Mathematics
1 answer:
Anni [7]3 years ago
3 0
2x^2+8x+7= \\
2(x^2+4x)+7= \\
2(x^2+4x+4-4)+7= \\
2((x+2)^2-4)+7= \\
2(x+2)^2-8+7= \\
2(x+2)^2-1 \\ \\
\boxed{y=2(x+2)^2-1}
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xenn [34]

Answer:

Constant= -22, 6

Variables=x,y

Coefficient= 4,5

5 0
3 years ago
PLEASEEEEE HELP PLEASEEEEE
nikdorinn [45]

Answer:

A=2t+29

B=5t+14

39 inches tall at equal height after 5 years

Step-by-step explanation:

Tree A at 5 years

2x5+29=39 inches

Tree B at 5 years

5x5+14=39 inches

7 0
3 years ago
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Two base angles of an isosceles triangle measure (3x + 2) and (5x – 30) degrees. How many degrees are in the third angle of the
joja [24]

Answer:

Step-by-step explanation:

Note that the base angle of an isosceles triangle is equal hence;

3x+2 = 5x-30

3x - 5x = -30-2

-2x = -32

x = -32/-2

x = 16

Hence one of the base angle = 3(16)+2 = 50degrees

The sum of angle in the triangle is 180, hence

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100 + y = 180

y = 80 degrees

Hence the third angle is 80 degrees

6 0
3 years ago
How do I solve this?
zmey [24]

Hey there!!

Multiply both the sides with 4/3.

Then we get

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8 0
4 years ago
What do you know about a quadratic equation that has the following points (2, 0) and (10, 0)?
Agata [3.3K]

Answer:

C.  The x-coordinate of the vertex must be 6

Step-by-step explanation:

The parabola intercepts the x-axis when y = 0.

Therefore, if the quadratic equation has the points (2, 0) and (10, 0) then the x-intercepts or "zeros" are x = 2 and x = 10.

The x-coordinate of the vertex is the midpoint of the zeros.

\sf \implies midpoint=\dfrac{2+10}{2}=6

Therefore, the solution is option C.

<u>Additional Information</u>

The leading coefficient of a quadratic tells us if the parabola opens upwards or downwards:

  • Positive leading coefficient = parabola opens upwards
  • Negative leading coefficient = parabola opens downwards

We have not been given this information and so therefore cannot determine the way in which it opens.

As we do not know the way in which way the parabola opens, we cannot determine if the parabola will have a negative or positive y-intercept.

We have not been given the full quadratic equation, and so we cannot determine if the parabola is wider (or narrower) than the parent function.

3 0
3 years ago
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