Answer: (x^2)/16 + (y^2)/25 = 1
Step-by-step explanation:
According to the problem we can figure out that the center of the ellipse is (0,0).
Since the foci is (0,3) and (0,-3) we know that the value of c is 3. The major vertices are (0,5) and (0,-5) so the value of a is 5.
If we put this into the equation a^2=b^2 + c^2, we get 25=9+ b^2
We get b^2 is 16
Now since we know that the ellipse is vertical because the x value didn’t change, we know that the b^2 value comes first in the equation. Then the a^2 value which is 25.
Answer:
54
Step-by-step explanation:
![\frac{4}{3} \pi r^{3} =12\pi \\r=\sqrt[3]{9} \\surface area 4\pi r^{2} = 4\pi (\sqrt[3]{9} )^2=54.372 (3dp)](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D%20%3D12%5Cpi%20%5C%5Cr%3D%5Csqrt%5B3%5D%7B9%7D%20%5C%5Csurface%20area%204%5Cpi%20r%5E%7B2%7D%20%3D%204%5Cpi%20%28%5Csqrt%5B3%5D%7B9%7D%20%29%5E2%3D54.372%20%283dp%29)
A quadratic function whose vertex is the same as the y-intercept has the equation
y=x^2+k (where k is the y-intercept, with vertex (0,k))
Since the vertex coincides with the y-intercept, the axis of symmetry is x=0.
The absolute value of -8 is 8
here’s a trick the absolute value of a positive is the same number of its negative it’s the same number but positive
hope it helps
