<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
Answer:
5
Step-by-step explanation:
4(5+n)=4(n+p)
20+4n=4n+4p
4p=20
p=20/4
p=5
From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.
<h3>Properties ofa rhombus</h3>
The given diagram is a rhombus that has the following properties
- Opposite side are equal
- All the sides are congruent
- The opposite angles are equal
- The sum of the adjacent angles are supplementary
From the figure shown, we can see that;
<msr is a right angle (equal to 90 degrees)
<mrh is acute since it is less than 90degrees.
Learn more on rhombus here: brainly.com/question/88523
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Question:
What is the greatest common factor (GCF) of 24 and 40?
Answer:
8
Step-by-step explanation: