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jekas [21]
3 years ago
13

For all functions of the form f(x)=ax^2+bx+c which is true when b=0

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0
I believe if b were to equal the value of 0, there would be 2 solutions to the function. Or not mainly if the resulting expression turns out to be a difference of squares.

Eg. f(x) = 2x^2 + 0x + 2

2x^2 + 2

2(x^2 + 1)

Here there would not be x intercepts, mainly because x cannot be solved.
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0.09 is 10 times as much as ?
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How many solutions does the system have?
amid [387]

Answer:

A; infinitely many solutions

Step-by-step explanation:

first, let's simplify the first equation to make it simpler.

divide both sides by 5

y=3x-8

new system

y=3x-8

y=3x-8

as you can see, they are the same.

not mandatory but useful!⬇⬇⬇⬇

just to be more clear, let's substitute them. since they're both already in y=, we can make them both set to each other.

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8 0
3 years ago
Is the relation a function? Why or why not?<br><br> {(–3, –2), (–1, 0), (1, 0), (5, –2)}
tankabanditka [31]

Answer:

yes, the given relation is a function.

Step-by-step explanation:

The given relation is

{(–3, –2), (–1, 0), (1, 0), (5, –2)}

A relation is called function if each element of the domain is paired with exactly one element of the range.

It means for each value of x there exist a unique value of y.

In the given relation for each value of x there exist a unique value of y.

Therefore the required solution is yes and this relation is a function.

5 0
3 years ago
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