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Allushta [10]
3 years ago
6

In the 1996 Summer Olympics Michael Johnson set a world record in the 200 m around with a time of 19.32 seconds this broke his r

ecord in the 1996 Olympic trials of 19.66 seconds how much faster was johnson it in the actual Olympics
Mathematics
1 answer:
sesenic [268]3 years ago
5 0
Johnson was 0.34 seconds faster in the actual Olympics
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200/40+15 = ??<br><br><br>helpp mee ^^ ​
wel

Answer:20   ^v^ Please follow me

Step-by-step explanation:

200/40=5

5+15=20

5 0
3 years ago
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Helpp, I need to determine the slope and y-intercept for each group. I need to write an equation for the graph in slope-intercep
jenyasd209 [6]

Answer:

Slope = -2

Y intercept = 4

Equation. y = -2x +5

Step-by-step explanation:

Using points, (1,2) and (3,-2)

Slope = (-2-2)/(3-1) = -4/2 = -2

Y intercept = 4

-2 = (y-3)/(x-1)

-2(x-1) = y-3

-2x +2 = y-3

y = -2x +2 +3

y = -2x +5

4 0
3 years ago
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In Ms. Craig’s class, 75% of the students are boys. There are 18 boys in the class. What is the total number of students in Ms.
topjm [15]

Answer:

24

Step-by-step explanation:

75% of x = 18

75/100 * x = 18 (x =  total number of students)

solving

x = 24

total number of students = 24

Checking:

75/100 * 24 = 18

5 0
3 years ago
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
3 years ago
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Abby takes a ride-sharing service to ride from her home to the mall. The ride-sharing service charges $1.75 per mile plus a one-
Dmitrij [34]

Answer:

do u know the awnser?

Step-by-step explanation:

7 0
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