Answer:
yes
Step-by-step explanation:
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
Write f(x) / g(x) = 1 / ((x+1)(x-2)).
It's easy to see that x cannot be -1 and 2;
So all real numbers exclude -1 and 2, which matches the second choice.
(2y+3)(3y^2+4y+5)
so u just multiply all the things from different brackets.
2y*3y^2 = 6y^3
2y*4y = 8y^2
2y*2 = 4y
3*3y^2 = 9y^2
3*4y = 12y
3*5 = 15
so 6y^3+8y^2+4y+9y^2+12y+15
thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:
6y^3+17y^2+16y+15
i hope this helps :)
someone correct me if im wrong
