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dlinn [17]
3 years ago
14

The least common multiple of 2 and 4

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

4

Step-by-step explanation:

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Please help me it's edgenuity laws of exponents ​
Roman55 [17]

Answer:

a = 10

b = 6

(a,b) = (10,6)

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y= 25x+500

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standard machine

Step-by-step explanation:

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A weather station in Antarctica reports that the temperature is currently -44 °C and has been rising at a constant rate of 4.5 °
-Dominant- [34]

Answer:

-17

Step-by-step explanation:

4.5*6=27

so -44++27

6 0
3 years ago
The diameter of a sphere is 21.6 cm. What is the sphere's volume? Round to the nearest tenth, if necessary.
NeX [460]
By definition, the volume of a sphere is:
 V =  \frac{4}{3}  (\pi) (r ^ 3)

 Where,
 r: sphere radio
 Substituting values we have:
 V =  \frac{4}{3}(3.14)(( \frac{21.6}{2} ) ^ 3)

 V = 5273.99424
 Rounding the result to the nearest tenth:
 V = 5274.0 cm ^ 3
 Answer:
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5 0
3 years ago
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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