3 years ago

points T, U, and B are collinear and U is between T and B. If TU = 4x-1, UB = 2x-1, and TB = 5x, find the volue of x.

1 answer:

4 0

Answer: 2

Step-by-step explanation:

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Bess [88]

Your answer is 175.

Hope this helps!

7 0

3 years ago

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

3 years ago

Rudiy27

Answer:

V = 672; SA = 544; LA = 448

Step-by-step explanation:

3 0

3 years ago

vesna_86 [32]

i can help if you have the picture

5 0

4 years ago

hoa [83]

Only the second one
when diameter is 4 r=2
so 2pi*2=2²*pi the first is circumference the second area

7 0

4 years ago