3 years ago

Simplify (8m2+m+7m2)-(3m-4m3+2m2)

1 answer:

4 0

$(8m^2+m+7m^2)-(3m-4m^3+2m^2)\\\\=8m^2+m+7m^2-3m+4m^3-2m^2\qquad|\text{combine like terms}\\\\=(4m^3)+(8m^2+7m^2-2m^2)+(m-3m)\\\\=4m^3+13m^2-2m$

You might be interested in

Lexi mailed a letter on Monday morning. The letter traveled 1/2 of a mile on Monday. It

BartSMP [9]

Answer:

1 1/4 miles

Step-by-step explanation:

3/4 + 2/4 (1/2 = 2/4) = 5/4 = 1 1/4

3 0

2 years ago

Read 2 more answers

The ratio of 9/5 is equal to

Nutka1998 [239]

The answer is 1 and 4/5. Just divide and put the remainder as the numerator and the numerator stays the same

6 0

3 years ago

Read 2 more answers

stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n

Anon25 [30]

Given functions are

$s(n)=2(1.1)^n+5_{}$ $d(n)=4(1.08)^n+3$

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

$t(n)=s(n)+d(n)$

$t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)$

$t(n)=2(1.1)^n+5+4(1.08)^n+3$

$t(n)=2(1.1)^n+4(1.08)^n+5+3$

$t(n)=2(1.1)^n+4(1.08)^n+8$

Taking 2 as common, we get

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

Hence The total number of ducks and swans in the lake after n months is

$t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack$

8 0

1 year ago

Solve for x in terms of a,b, and c: ax - 3b =c. . 1: a(c+3b). 2: a (c-3b). 3: c-3/a. 4: c+3b/a

trapecia [35]

We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a

8 0

3 years ago

In the centerville during the month of February the sun didn’t shine on 75% of

melomori [17]

Hey there
So you can find the answer by dividing 28/4 which will get you 7 so we now multiple 7 By three so that we can find what 3/4 of 28 is which equals 21 days so the sun didn't sine for 21 days.

6 0

3 years ago

Read 2 more answers