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r-ruslan [8.4K]
3 years ago
10

What’s the answer ?

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

There is no image

Step-by-step explanation:

ankoles [38]3 years ago
4 0

Answer: i dont see a image

Step-by-step explanation:

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What is 20.30 - 19.70 and what are the solving steps?
DIA [1.3K]

Answer

0.6

Step-by-step explanation:

here is the working out! Can i get brainliest

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3 years ago
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cluponka [151]
42 6 7 times is 42 so the answer will be 42
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Explain the steps that are necessary to solve 4x - 2(x + 3) = x + 1
Sidana [21]
So you would distribute what's in the parenthesis and end up with 4x-2x-6=x+1, then you combine like terms and end up with 2x-6=x+1, now you can add 6 to both sides or subtract 1 both sides (basically anything goes for this step just make sure you apply the same thing on both sides) so I'll add 6 and continue just to show you... then you end up with 2x=x+7 then you subtract 1x on both sides to get x=7. sorry it's a lot hopefully you get it know!
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3 years ago
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{2, -1, -4, -7, ...}
lesantik [10]

Answer:

-3 every time

Step-by-step explanation:

3 0
3 years ago
The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive
murzikaleks [220]

Answer:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

X \sim Unif (a=0, b =12)

And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0
3 years ago
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