I did im in algebra 1 now
5 days food for 150 students suggests there was 750 day rations
If there was 100 students this would last 750/100 = 7.5 days.
If it ran out after 4 days there were 750/4 = 187 students (187.5 not valid)
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
Answer:
45
Step-by-step explanation:
Answer:
new slope = 4/3
Step-by-step explanation:
-3/8 is perpendicular to the new slope
=> new slope = -8/3 * -1/2
= 8/6
= 4/3
please give me brainliest if it is helpful for you
