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Ierofanga [76]
3 years ago
9

Can someone check this for me thanks so much

Mathematics
2 answers:
adell [148]3 years ago
6 0
It looks like it’s correct
Zinaida [17]3 years ago
3 0

Answer:

that looks like it is right

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Solve the blank: This equation for this graph is y=____x + _______​
Marysya12 [62]

Answer:

y=3x+2

Step-by-step explanation:

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3 years ago
A factory can fill 225 bottles of orange juice each hour. Each bottle of orange juice contains 24 fluid ounces. Each bottle of j
lozanna [386]

Answer:

27 i think

Step-by-step explanation:

I divided them to make sure its right im not 100 percent sure tho

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3 years ago
Which ordered pair is a solution of the equation? 5x-2y=18
irakobra [83]

Answer:

(2, -4)

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
1.A cube has side lengths of 15 inches, what is the surface area and volume of the cube? 2. A cube has side lengths of 8 inches,
omeli [17]

Answer:

Cube 1: 3375 cubed inches, 1350 inches squared.

Cube 2: 512 cubed inches, 384 inches squared.

Step-by-step explanation:

Formula for Volume of a Cube:  V=s^3\\ (s - side length)

Formula for Surface Area of a Cube: SA=6s^2 (s- side length)

<h3>For Cube 1:</h3>

The side length's 15 inches.

Find the volume:

V=15^3\\\rightarrow 15*15*15=3375\\\boxed {V=3375}

The volume of cube one is 3375in³.

Find the surface area:

SA=6(15)^2\\\rightarrow 15^2 = 225\\SA = 6 * 225\\\boxed {SA=1350}

The surface area of cube 1 is 1350in².

<h3>For Cube 2:</h3>

The side length's 8 inches.

Find the volume:

V=8^3\\\rightarrow 8*8*8= 512\\\boxed {V=512}

The volume of cube two is 512in³.

Find the surface area:

SA=6(8)^2\\\rightarrow 8^2=64\\SA=6*64\\\boxed {SA=384}

The surface area of cube 2 is 384in².

<em>Brainilest Appreciated. </em>

3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
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