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Nonamiya [84]
2 years ago
8

Help me please, will give brainliest​

Mathematics
2 answers:
liq [111]2 years ago
8 0

Step-by-step explanation:

Mark me as brilliant plzzz

Alona [7]2 years ago
6 0

When x=4

1. Substitute the x into the equation.

y=3(4)+10

2. Solve for y

y=3(4)+10

y=12+10

y=22

When x=5

1. Substitute the x into the equation.

y=3(5)+10

2. Solve for y

y=3(5)+10

y=15+10

y=25

When x=6

1. Substitute the x into the equation.

y=3(6)+10

2. Solve for y

y=3(6)+10

y=18+10

y=28

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The answer is y = 5.5x, so B
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If T(n)=3n-1,what is the 3rd term?
exis [7]
Plug in 3 for n, since you're looking for the third term.
T(1) = 3(1) - 1 = 2
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3 years ago
For each set of three lengths determine if they can be the side lengths of a triangle
Luden [163]

Answer:

1) Yes

2) No

3) Yes

4) Yes

Step-by-step explanation:

Remember the rule: the sum of the two shortest sides must be bigger than the longest side. From there, the answers should be obvious. Just add up the smallest sides for each triplet of lengths and see if that is bigger than the largest side.

7 + 14 > 18, therefore this can be a triangle

3 + 8 < 17, therefore this can't be a triangle

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5 0
2 years ago
Find the area of a circle with a radius of 6 centimeters. Use 3.14 for π.
Nataliya [291]

Answer:

28.27

Step-by-step explanation:

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8 0
3 years ago
Bill Ding plans to build a new hardware store. He buys a rectangular lot that is 50 ft by 200 ft, the 50-ft dimension being alon
enot [183]

Answer:

Length a = 59.62

Width b = 67.09

Cost = $10,734.4

Step-by-step explanation:

Solution:

Let a be the length and b be the width.

Area of the rectangle = a x b

a x b = 4000

Cost of the construction:

Cost = 100a + 80(a + 2b)

Cost = 100a + 80a + 160b

Cost = 180a + 160b     Equation of the Cost of the construction.

Now, we need a and b to calculate the minimum cost required to build a lot.

From the area = a x b

we have,

a x b = 4000

b = 4000/a

Putting this equation into the cost of the construction.

We get:

Cost = 180a + 160 x (4000/a)

Cost = 180a + 640000/a

Differentiating with respect to a, we get

C^{'} = 180 - 640000/a^{2}

Putting C^{'} = 0

180 - 640000/a^{2} = 0

Taking LCM

180a^{2} - 640000 = 0

Solving for a

180a^{2} = 640000

a^{2} = 640000/180

a^{2} = 3555.55

Taking square root

a = 59.62

As we know,

b = 4000/a

putting the minimum value of a  = 59.62

b = 4000/59.62

b = 67.09

So, now we have both the dimensions a and b

Putting the values of a and b we will get the cost of the construction.

Cost = 180a + 160b

Cost = 180(59.62) + 160(67.09)

Cost = $10,734.4

Hence, $10,734.4 will be the minimum cost of the construction for Bill Ding.    

5 0
2 years ago
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