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3 years ago

solve for A=lw for l. then find the length of a rectangle with a width of 50 millimeters and an are of 250 square millimeters

Mathematics

2 answers:

hammer [34]3 years ago

6 0

75 hopefully it’s right sorry if it’s wrong

maksim [4K]3 years ago

5 0

Answer:

Step-by-step explanation:

$\frac{250}{2}$ -50

125-50

=75

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Fam what is 25 x 25 please help me fam needd the answer ASAP!

Vlada [557]

Answer:

it is 625

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

2 years ago

What is the answer? -3(6w-3v-1)

SashulF [63]

This is the best way to show you step by step. i love this website/app it’s called Math papa and you type in your problem and it helps you with the steps. this is how i got so good at math.

4 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

What is thesimlified form of sqrt(48n^9)

garik1379 [7]

4n^4 √3n I believe would be the simplified form.

4 0

4 years ago