Answer: 120
Step-by-step explanation:
explanation down below↓
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1 answer:
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Depends on where you are in the math book but this would be the most simple way.
n= number
sqar(-1) = i
n= number
sqar(-1) = i
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>x on the interval [0, 2π)
<h3>Solution</h3>Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
The solution to the inequality is:
The solution graph is also attached below.
Step-by-step explanation:
Given
We are given the expression
To determine
Solve for x
Given the expression
Subtract 5 from both sides
Simplify
Multiply both sides by 3
Simplify
Thus, we conclude that:
Therefore, the solution to the inequality is:
The solution graph is also attached below.
