<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.
p=2w+2w=520=4w
w=130
Area
A=wL=130(130)= 16900 square yards</span>
1 + 54 = 55
2 + 53 = 55
3 + 52 = 55
4 + 51 = 55
5 + 50 = 55
6 + 49 = 55
7 + 48 = 55
8 + 47 = 55
9 + 46 = 55
10 + 45 = 55
and so on...
I hope that helps. :)
In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call
) and the length of the hypotenuse. This sets you up with the relation
In 23, you're given a similar situation, except now you're looking for the angle (I'll call it
) in the triangle opposite the side denoting the height of the airplane. So this time,
Answer:
7 is the answer.
Step-by-step explanation:
In equations like this, you would solve the numbers in the parenthesis first, and then gradually do: Multiplication -> Division -> addition -> subtraction.
Therefore, -18 / 9 is -2.
-2 * 2 would be -4,
11 + (-4) would be 7.
Answer : 7.
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
