NEED HELP ASAP PLEASE!! The provided diagram of triangle ABC will help you to prove that the base angles of an isosceles triangl
e are congruent. The first step is to draw auxiliary line AO. What must be true about in order to complete the proof using the ASA (Angle Side Angle) triangle congruency theorem? Classify each statement as needed or not needed to complete the proof.
1 answer:
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
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Answer:
y =
Step-by-step explanation:
First, we need to rearrange the equation to make it y = mx + c
4x - y = 3
y + 3 = 4x
y = 4x -3
So the slope of the line is 4.
The slope of a line perpendicular to an equation is:
So the slope of the perpendicular line is:
= -0.25
Now to find the equation of a line you can use the following equation:
y - y₁ = m(x - x₁)
Where y₁ is the y-coordinate, x₁ is the x-coordinate and m is the gradient. Plug the values in:
y₁ = 6
x₁ = -5
m =
y - 6 = (x - - 5)
To get rid of the fraction we need to multiply the whole equation by 4:
4y - 24 = -1(x - - 5)
The two negatives cancel out:
4y - 24 = -1(x + 5)
Multiply the brackets out:
4y - 24 = -x + 5
Now, to rearrange the formula back into y = mx + c
Move the -24 over to the other side making it a +24:
4y = 2x + 5 + 24
4y = 2x + 29
Divide everything by 4:
y =
y =
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