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Murrr4er [49]
3 years ago
15

A portion of the Quadratic Formula proof is shown. Fill in the missing statement. Statements Reasons x squared plus b over a tim

es x plus the quantity b over 2 times a squared equals negative 4 times a times c all over 4 times a squared plus b squared over 4 a squared Find a common denominator on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Add the fractions together on the right side of the equation the quantity x plus b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Rewrite the perfect square trinomial on the left side of the equation as a binomial squared ? Take the square root of both sides of the equation x plus b over 2 times a equals plus or minus the square root of the quantity b squared minus 4 times a times c end quantity, all over 4 times a squared x plus b over 2 times a all squared equals plus or minus b squared minus 4 times a times c, all over 4 times a squared all squared the square root of x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared
Mathematics
2 answers:
expeople1 [14]3 years ago
3 0

Answer:

is this multiplication ?

Step-by-step explanation:

vagabundo [1.1K]3 years ago
3 0

Answer: A just put A

Option A.

Step-by-step explanation:

we have

Simplify the right side of the equation

we know that

so

The expression is

therefore

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

bezglasnaaz and 17 more users found this answer helpful

THANKS

9

3.0

(9 votes)

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lapo4ka [179]

A hexagonal prism should work! The two bases are hexagons, and there are 6 lateral faces that are rectangles. When you count the edges, there are 18

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3 years ago
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Use the equation below to find y, if m=11, x=2, and b=5.<br>y=mx+b​
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A 2-kg object is fired from a cannon at a 30º angle wrt to the horizontal. the initial speed is 35 m/s. how high will the object
kompoz [17]
     <span> You have :
----------------

v0 = 35 m/s

B = angle of elevation = 30 deg

a suby = - g

v suby0 = ( v0 ) ( sin B )

v suby0 = ( 35 m/s ) ( sin 30 ) = 17.5 m/s

At maximum height :
------------------------------

v suby = vy* = 0.0

t = t*

y = ymax = y*

Basic kinematics gives :
-------------------------------------

a suby = dv suby / dt = -g ------> dt = dv suby /a suby

v suby = dy/dt ------> dt = dy / vsuby

dt = dv suby / a suby = dy / v suby

( v suby ) ( d v suby) = ( a suby ) dy = ( -g ) dy

Now integrate and get :
-----------------------------------

( v suby* )^2 - ( v suby0)^2 ( 1/2 ) = ( -g ) ( ymax )

ymax = [ ( v suby0 )^2 - ( v suby* )^2 ] / [ ( 2 ) ( g ) ]

ymax = ( 17.5 m/s )^2 - ( 0.0 m/s )^2 ] / [ ( 2 ) ( 9.807 m/s^2 ) ]

ymax = 15.6 m <------------------

Check the result:
--------------------------

t* = v suby0 / g = ( 17.5 m/s ) / ( 9.807 m/s^2 ) = 1.784 s

y* - y0 = ( v suby0 ) ( t* ) - ( g/2 ) ( t* )^2

y* = ( 17.5 m/s ) ( 1.784 s ) - ( 9.807 m/s^2 / 2 ) ( 1.784 s )^2

y* = ymax = 31.23 m - 15.61 m = 15.6 m

The ymax values agree.</span>
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3 years ago
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