Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
44 cm
Step-by-step explanation:
You have to find the area of the bigger square and find the area of the smaller one. (Width x Height). Then subtract the smaller rectangle from the bigher one
Answer:
c that is the answer yes .
Answer: He was killed 24.83 hours before the body was found.
Step-by-step explanation:
Since we have given that

Here, T is the temperature of a body t hr after death, T = 82°F
T₀ is the air temperature , T₀ = 67°F
T₁ is the body temperature at the time of death = T₁ = 98.6°F
So, we will substitute all the values in the above equation.

Hence, he was killed 24.83 hours before the body was found.