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Marat540 [252]
3 years ago
10

Ed had a piece of rope 6 3/4 ft long. he cut of 3/8 ft. how much rope did ed have left? enter you answer in the box as a mixed n

umber in simplest form
Mathematics
1 answer:
Ann [662]3 years ago
3 0

Let's first convert the first number to an improper fraction so we can perform arithmetic on it:

6\frac{3}{4} =\frac{27}{4}

Now, let's get common denominators. Since 3/8 has a denominator of 8, we can multiply our, newly found, improper fraction by 2 to get a denominator of 8:

\frac{27}{4} *2=\frac{54}{8}

Next, subtract (because Ed cuts the rope):

\frac{54}{8} -\frac{3}{8} =\frac{51}{8}

Last step is to convert it back into a mixed fraction:

\frac{51}{8} =6\frac{3}{8}

So, your final answer is 6 and 3/8. Hope I could help, and let me know if I can do anything else for you! :)


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3 years ago
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Two trains arrived at a station at 2:55 P.M., with one arriving on Track A, and the other arriving on Track B. Trains arrive on
My name is Ann [436]

Answer:

B) 5:19 P.M.

Step-by-step explanation:

Given that two trains arrived at a station at 2:55 P.M., with one arriving on Track A, and the other arriving on Track B. Trains arrive on Track A every 16 minutes, and they arrive on Track B every 18 minutes.

Now we need to find about at what time will trains next arrive at the same time on both tracks.

Then next time trains arrive at the same time on both tracks. can be found by taking least common multiple of 16 and 18 minutes.

Multiples of 16 and 18 are

16 32 48 64 80 96 112 128 144 160

18 36 54 72 90 108 126 144 162 180

Least common multiple of both is 144

Hence both trains will arrive at the same time after 144 minutes

or at (2:55 PM+144 minutes)

= (2 hours 55 min)+(144 min) PM

= (2 hours 55 min)+(2 hours 24 min) PM

= (2 hours 55 min)+(2 hours 24 min) PM

= 5 hours 19 minutes

Hence correct choice is B) 5:19 P.M.

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3 years ago
Which point on the number line represents the product of 4 and –2?
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The point on the number line would be 2
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A car passes a landmark on a highway traveling at a constant rate of 40 kilometers per hour. Two hours later, a second car passe
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So first you want to find how much the second car gains on the first car in one hour.

Since the second car travels 65 kph, but the first travels 40, we can just subtract 40 from 65 to find how much faster the second car is than the first.

65 - 40 = 25

So the second car is 25 kph faster than the first.

Since the first car had a 2 hour head start, we first want to calculate how far away the first car got from the sign before the second car reached the sign.

So just 2 hours * 40 kph, which gives you 80 kilometers.

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Since the second car gains 25 km per hour on the first car, we can just divide 80 by 25.

80 / 25 = 16/5, or in decimal form 3.2.

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