Find algebraically in RxR using substituting method the S.S. of the two equations:
2 answers:
Answer:
x=3 y=1
Step-by-step explanation:
x+y=4
y=-x+4
plug in the y
2x-(-x+4)=5
2x+x-4=5
3x=9
x=3
plug in x=3 into first equation to find y
y=-(3)+4
y=-3+4
y=1
Answer:
Step-by-step explanation:
x + y = 4 equation 1
2x - y = 5 equation 2
using substitution method,
x= 4 - y equation 3
substitute equation 3 into equation 2
2(4-y) -y = 5
8 - 2y - y = 5
8 - 3y = 5
-3y = 5 - 8
-3y = -3
divide through by -3
-3y/-3 = -3/-3
y = 1
substitue the value of y into equation 1
x + y = 4
x + 1 = 4
x = 4 - 1
x = 3
Hence, x = 3 and y = 1
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6+9-4+12+9=32.
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Pythagorean theorem
Answer:
ones
Step-by-step explanation:
Answer:
x = 12/13
BC = 140/13
Step-by-step explanation:
If A is the mipoint of BC, then AB is half of BC.
AB = BC / 2
8x − 2 = (3x + 8) / 2
16x − 4 = 3x + 8
13x = 12
x = 12/13
BC = 3x + 8
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BC = 140/13
