Question

Find algebraically in RxR using substituting method the S.S. of the two equations:

Answer 1

Answer:

x=3 y=1

Step-by-step explanation:

x+y=4

y=-x+4

plug in the y

2x-(-x+4)=5

2x+x-4=5

3x=9

x=3

plug in x=3 into first equation to find y

y=-(3)+4

y=-3+4

y=1

Answer 2

Answer:

Step-by-step explanation:

x + y = 4   equation 1

2x - y = 5  equation 2

using substitution method,

x= 4 - y  equation 3

substitute equation 3 into equation 2

2(4-y) -y = 5

8 - 2y - y = 5

8 - 3y = 5

-3y = 5 - 8

-3y = -3

divide through by -3

-3y/-3 = -3/-3

y = 1

substitue the value of y into equation 1

x + y = 4

x + 1 = 4

x = 4 - 1

x = 3

Hence, x = 3 and y = 1