The standard equation for a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at (h,k)
For this problem, the center is at (3,2). The abscissa and the ordinate are all positive. So this must be located on the first quadrant.
Hence, the answer is <span>It is located in the first quadrant..</span>
None of the above. 11^8/11^3 is 11^5 since you will just subtract exponents. The numerical value is 161051
although you should have an option that either is 11^5 or equals 11^5 like 11^15/11^10 for example
the third answer is almost correct, but it would have to be 11^5/11^0
-2x + 3a - 6 - 5x - 7a....combine like terms
-7x - 4a - 6 <==
22-12=10
1 problem every minute he would finish in 10 minutes