Answer:
180cm^2 & 472ft^2
Step-by-step explanation:
answer of 16 number
h2=p2+b2 ,therefore
h=100+80
h=180
answer of question 17
h2=p2+b2
576=p2+104
576-104=p2
472=p2
First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
Answer:
-14
Step-by-step explanation:
You've got a(1)=20
a(1) means a(n) when n=1
the sequence is telling you to take the previous value of a(n), which is a(n-1) and subtract 17
then:
a(2) = a(1)-17 = 20 - 17 = 3
a(3) = a(2) - 17 = 3-17 = -14
This problem can be solved from first principles, case by case. However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.
Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected
Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}
Therefore the
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}
