The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
Rearrange the formula to solve for time. Which is the distance over the rate. Then divide 546 meters by 1.3 meters per second. The meter units cancel each other out leaving you with : t: 420.
F(x) = -x^2 + 6x + 6
where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds
rate of change of a distance is speed
at x=5, distance = 11
at x=2, distance = 14
so average rate of change = (14-11)/(5-2) = 1
so ans is D
Stimulus.
A stimulus is a reaction to environmental changes.
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