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Ainat [17]
4 years ago
7

URGENT!! EASY IM DUMB MY LAST QUESTION WILL FOREVER BE GRATEFUL PLS HELP WILL GIVE BRANLIEST!! AT LEAST TAKE A LOOK!!!! PLS I AM

BEGGING!!!
YOU HAVE TO LOOK CLOSLY TO SEE THE NUMBERS ON THE TRIANGLE
IN CASE YOU CANNOT ON THE LEFT IT IS 15CM AND ON THE BOTTOM IT IS 14 CM

Find the unknown side of the triangle below (round to the nearest tenth).
A) 20.5 cm
B) 210.5 cm
C) 5.4 cm
D) 16 cm

Mathematics
1 answer:
insens350 [35]4 years ago
7 0

Answer:

A. 20.5

Step-by-step explanation:

We can use the Pythagorean theorem to solve this equation for the missing side length, X.

a^2 + b^2 = c^2

We have a and b, we just need c, the hypotenuse.

14^2 + 15^2 = c^2

196 + 225 = c^2

421 = c^2

Now, we will square both sides:

The answer is about 20.5

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If a line is perpendicular to a line segment, what angle do they form at their intersection?
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Perpendicular lines form 90 degree angles.
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Which equation represents a line passing through the point (8,33) with a slope of 3?
Delvig [45]

The slope intercept form of equation of required line is y = 3x + 9

What is equation of line in slope intercept form?

The most general form of equation of line in slope intercept form is given by y = mx + c

Where m is the slope of the line and c is the y intercept of the line.

Slope of a line is the tangent of the angle that the line makes with the positive direction of x axis.

If  \theta is the angle that the line makes with the positive direction of x axis, then slope (m) is given by

m =  tan\theta

The distance from the origin to the point where the line cuts the x axis is the x intercept of the line.

The distance from the origin to the point where the line cuts the y axis is the y intercept of the line.

Here,

Slope = 3

The line passes through (8, 33)

Equation of required line

y - 33 = 3(x - 8)

y - 33 = 3x - 24

y = 3x - 24 + 33

y = 3x + 9

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Which estimate best describes the area under the curve in square units?
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Use the definition of continuity and the properties of limits to show that the function f(x)=x sqrtx/(x-6)^2 is continuous at x
qaws [65]

Answer:

The function is  continuous at  x = 36

Step-by-step explanation:

From the question we are told that

      The  function is f(x)  =  x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }  

       The  point at which continuity is tested is  x =  1

Now from the definition  of continuity ,

   At function is continuous at  k if  only  

       \lim_{x \to k}f(x)  =  f(k)

So

      \lim_{x \to 36}f(x)  =  \lim_{n \to 36}[x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }]

                            = 36 *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

                             = 7.2

Now  

     f(36) = 36  *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

     f(36) = 7.2

So  the given function is continuous at  x =  36

because

          \lim_{x \to 36}f(x)  =  f(36)

7 0
3 years ago
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