Answer:
![y=(x-2)^2-1](https://tex.z-dn.net/?f=y%3D%28x-2%29%5E2-1)
Step-by-step explanation:
<u>Complete the square</u>
<u />![y=x^2-4x+3\\\\y+1=x^2-4x+3+1\\\\y+1=x^2-4x+4\\\\y+1=(x-2)^2\\\\y=(x-2)^2-1](https://tex.z-dn.net/?f=y%3Dx%5E2-4x%2B3%5C%5C%5C%5Cy%2B1%3Dx%5E2-4x%2B3%2B1%5C%5C%5C%5Cy%2B1%3Dx%5E2-4x%2B4%5C%5C%5C%5Cy%2B1%3D%28x-2%29%5E2%5C%5C%5C%5Cy%3D%28x-2%29%5E2-1)
Answer:
23, 25, 27
Step-by-step explanation:
first integer will be X, second will be (X+2), and the third will be (X+4). They will all be summed up and set equal to 75.
![(x) + (x + 2) + (x + 4) = 75](https://tex.z-dn.net/?f=%28x%29%20%2B%20%28x%20%2B%202%29%20%2B%20%28x%20%2B%204%29%20%3D%2075)
combine like terms:
![3x + 6 = 75](https://tex.z-dn.net/?f=3x%20%2B%206%20%3D%2075)
subtract 6:
![3x = 69](https://tex.z-dn.net/?f=3x%20%3D%2069)
divide by 3 to find value of X:
![\frac{3x}{3} = \frac{69}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7B69%7D%7B3%7D%20)
![x = 23](https://tex.z-dn.net/?f=x%20%3D%2023)
plug in X in o red der to finger the rest of the integers.
(X+2)= (23+2)=25
(X+4)= (23+4)=27
Answer:
scientific notation ------> 2.56*<em>10^11 bits</em>
<em>(10 to the power of 11 (10^11)</em>
standard notation -----> 256,000,000,000 bits
Step-by-step explanation:
hope this helped