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Aleks04 [339]
3 years ago
10

Need help with this question. I tried simplifying the radical, but apparently it’s not the answer

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

-1/5+(√3)/20i   or   -0.2+0.05√3i

Step-by-step explanation:

  \dfrac{-8+\sqrt{-12}}{40}=-\dfrac{8}{40}+\dfrac{2\sqrt{3}i}{40}=\boxed{-\dfrac{1}{5}+\dfrac{1}{20}\sqrt{3}\,i=-0.2+0.05\sqrt{3}\,i}

_____

<em>Comment on answer form</em>

Satisfying the input format requirements of a computer is always problematic. One never knows if fractions or decimals are preferred, whether radicals must be simplified, and so on. If no clues are offered by general instructions, other questions, or previous experience, then it might be useful to consult your instructor.

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Hey! please help i’ll give brainliest! if it lets me:)
lozanna [386]

Answer:

south since its the opposite

5 0
3 years ago
The circumference of the base of a cone is 24 inches. The slant height of the cone is 20 inches.
loris [4]

The surface area of a cone with circumference base of 24π inches and slant height of 20 inches is 384π inches² in terms of π.

<h3>Surface area of a cone</h3>

surface area = πr(r + l)

where

  • r = radius
  • l = slant height

Therefore,

l = 20 inches

24π = 2πr

r = 12

Therefore,

surface area  = π(12)(12 + 20)

surface area = 12π(12 + 20)

surface area = 12π × 32

surface area = 384π inches²

learn more on surface area here: brainly.com/question/2847956

6 0
2 years ago
Read 2 more answers
What are the vertical and horizontal asymptotes for the function f(x)=3^2/x^-4
Zarrin [17]

The vertical asymptotes x = - 2, 2 and Horizontal asymptotes y = 3

Option A is the correct answer.

<h3>What are Function?</h3>

Function are mathematical statement which links an independent variable to dependent variable.

It always comes with a defined domain and range.

The equation mentioned is incorrect in the question w.r.t. to the solutions mentioned, The right equation is

\rm f(x) = \dfrac{3 x^2}{x^{2}-4}

This function can also be written as

\rm f(x) = \dfrac{3 x^2}{x^{2}-2^2}\\\\\rm f(x) = \dfrac{3 x^2}{(x+2)(x-2)}

Vertical asymptotes are defined when the denominator of a rational function tends to zero.

To find the equation/s let the denominator equal zero.

Denominator tends to zero for x = -2 and x = +2

Horizontal Asymptote is when the function f(x) is tending to zero.

for x = +∞ and x = - ∞

Let the rational function f(x)= \dfrac{mx^a}{nx^b}  where  and a and b are degree of numerator and denominator.

If a < b , then the y axis y = 0 is a horizontal asymptote.

If b = a then horizontal asymptote is the line y = p/q

Here the value is b = 2 and a = 2

Since b = a the horizontal asymptote is the line

y = m/n  where m = 3 and n = 1

Therefore y = 3

So , vertical asymptotes x = - 2, 2

Horizontal asymptotes y = 3

Option A is the correct answer.

To know more about Function

brainly.com/question/12431044

#SPJ1

8 0
2 years ago
Measure the length of the paper clip to the nearest tenth of a centimeter.
Solnce55 [7]
3 cm since the end is closer to the 3 than it is to 4
3 0
3 years ago
Read 2 more answers
If 1 dollar = 100 cents<br><br> Then what is 46,300 cents in dollars?
Marizza181 [45]

Answer: Hi correct answer is $463

Step-by-step explanation:

Thank you please mark me brainlest.:D

3 0
3 years ago
Read 2 more answers
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