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2 years ago

The sides of an equilateral triangle are all 8 units long. What is the length of the triangle’s altitude?

Mathematics

1 answer:

True [87]2 years ago

5 0

Answer:

B or 4 $\sqrt[]{3}$

Step-by-step explanation:

I could be wrong as I'm very new to this math but I believe its 4 $\sqrt{3}$

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iris [78.8K]

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2 years ago

HELP PLEASE ASAPPPP!!

MakcuM [25]

Answer:

Step-by-step explanation:

(10/y + 13) -3

Let y=5

(10/5 + 13) -3

PEMDAS says parentheses first

(2 +13) -3

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2 years ago

The length of the base of an isosceles triangle is x. The length of a leg is 2x - 2. The perimeter of the triangle is 71. Find

Elanso [62]

Answer:

x = 15

Step-by-step explanation:

x + 2x - 2 + 2x - 2 = 71

Solve for x, you get 15.

3 0

1 year ago

Consider points A (3, 6) and B (8, 4). Find point C on the x-axis so AC + BC is a

scoray [572]

Answer:

(1,2)

Step-by-step explanation:

the st. lines 3x+4y=5 and 4x-3y=15 interrect at a point A(3, -1. On these linepoints B and C are chosen so that AB= AC. find the posible eqns of the lineBC pathrough the point

6 0

2 years ago

What is the greatest common factor of 44c5,22c3 and 11c4?

elena-s [515]

Answer:

The greatest common factor of the given expressions is

$11c^3$

Step-by-step explanation:

Given that $44c^5,22c^3,11c^4$

$44c^5$ can be written as

$11\times 4\times c^3\times c^2$

$22c^3$ can be written as

$11\times 2\times c^3$

and $11c^4$ can be written as

$11\times 1\times c^3\times c$

Comparing the common factors we have $11\times c^3$ is the greatest common factor of $44c^5,22c^3,11c^4$

Therefore the greatest common factor of the given expressions is

$11c^3$

3 0

2 years ago