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FinnZ [79.3K]
2 years ago
12

For a system of linear equations, the solution for the system is__

Mathematics
1 answer:
amm18122 years ago
8 0
For a system of linear equations, the solution for the system is____.

Answer: The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently. In this example, the ordered pair (4,7) is the solution to the system of linear equations.
Picture:

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4.12 rounded to the nearest tenth is 4.1
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Convert the following equation to slope-intercept form:<br> 5x - 15y = 105
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Answer:

D

Step-by-step explanation:

You need to solve the equation so that it looks like y = mb + b

So -15y = -5x + 105, then divide both sides by -15 so y = -5/-15 x + 105/-15

y = \frac{1}{3} x  - 7

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Help on number nine please?​
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Example 4: Converting Rational Numbers to Decin
IceJOKER [234]

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3 years ago
Show how to find the roots (zeros) of the function in the picture below.
Vikki [24]

Answer:

The roots (zeros) of the function are:

x=5,\:x=-8

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+3x-40

substitute f(x) = 0 to determine the zeros of the function

0=x^2+3x-40

First break the expression x² + 3x - 40  into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x:  x(x - 5)

Factor out 8 from 8x - 40:  8(x - 5)

Thus, the expression becomes

0=x\left(x-5\right)+8\left(x-5\right)

switch the sides

x\left(x-5\right)+8\left(x-5\right)=0

Factor out common term x - 5

(x - 5) (x + 8) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x-5=0\quad \mathrm{or}\quad \:x+8=0

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

x=5,\:x=-8

6 0
3 years ago
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