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dusya [7]
3 years ago
8

A line passes through the points (4,6) and (6,2)

Mathematics
2 answers:
beks73 [17]3 years ago
6 0
Um i think it is yes,no,no,yes,yes,yes
navik [9.2K]3 years ago
4 0

Answer:

Option 2 and option 6 are correct which is (y-6)=-2(x-4)  and (y-2)=-2(x-6)  respectively.

Step-by-step explanation:

We have been given two points (4,6) and (6,2)

We have formula for equation of a line which is

(y-y_1)=m(x-x_1)

Where m=\frac{y_2-y_1}{x_2-x_1}

Here, {x_1=4,y_1=6,x_2=6,y_2=2

On substituting the values  we will get  m=\frac{2-6}{6-4}=-2

Now, substituting values in (y-y_1)=m(x-x_1) we will get

(y-6)=-2(x-4)

If we choose  x_1=6,y_1=2,x_2=4,y_2=6 then substituting the values in (y-y_1)=m(x-x_1) we will get

(y-2)=-2(x-6)

Therefore,option 2 and option 6 are correct.

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Sin(θ-30) = cos(θ)<br>solve for θ.​
Margaret [11]

Answer:

Step-by-step explanation:

sin(θ+30∘)=cos50∘

⟹cos(90∘−(θ+30∘))=cos50∘

⟹cos(60∘−θ)=cos50∘

⟹cos(π3−θ)=cos5π18

Writing the general solution as follows

π3−θ=2nπ±5π18

⟹θ=π3−(2nπ±5π18)

Method 2: ,

sin(θ+30∘)=cos50∘

⟹sin(θ+30∘)=sin(90∘−50∘)

⟹sin(θ+30∘)=sin40∘

⟹sin(θ+π6)=sin2π9

Writing the general solution as follows

θ+π6=2nπ+2π9

⟹θ=2nπ+2π9−π6

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or

θ+π6=(2n+1)π−2π9

⟹θ=2nπ+π−2π9−π6

⟹θ=2nπ+11π18

Hint 1: sin(a)=sin(b) iff a−b=2kπ or a+b=(2k+1)π for some k∈Z.

Hint 2: cos(40∘)=sin(50∘).

Hint:

sinθ=cos(90∘−θ)

cos50∘=sin40∘

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0

Knowing the relation between sin(θ) and cos(θ) is quite crucial. One of the major relation is that the sine function and cosine function are fairly similar with 90∘ difference so,

Sin(x+90)=cos(x)

We are given x=50, so

x+90=30+θ

θ=110

or

180−140=40

This is θ+30 so,

θ=10∘

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3 years ago
Enter the equation of the line in the form y=mx where m is the slope.Immersive Reader
kari74 [83]

Answer:

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