2 years ago

What is the perimeter of quadrilateral ABCD?

Mathematics

1 answer:

Bogdan [553]2 years ago

5 0

Answer:

I believe it is 18 + the square root of 26.

Step-by-step explanation:

The slope of line BC should be 5/1 because it goes up 5 times and to the right once. If you square root 26 you get 5.09.

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \sf \dashrightarrow \: \dfrac{d}{dx}(76x + 1)$

$\qquad \sf \dashrightarrow \:76 {x}^{1 - 1} + 0$

$\qquad \sf \dashrightarrow \:76 {x}^{0} + 0$

$\qquad \sf \dashrightarrow \:76$

Here, we have got a constant number, therefore for any value of x it will be 76

Therefore, derivative of 76x + 1 at x = 1 is 76

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