1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dem82 [27]
3 years ago
15

The projectile motion of an object can be modeled using s(t)=gt^2+v0t+s0, where g is the acceleration due to gravity, t is the t

ime in seconds since launch ,s(t) is the height after t seconds,v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is -4.9m/s^2. A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds?
Mathematics
2 answers:
defon3 years ago
8 0

Answer:

the answer is a

Step-by-step explanation:

edge2020

RSB [31]3 years ago
7 0

Answer:

S(t) = -4.9t^2 + Vot + 282.24

Step-by-step explanation:

Since the rocket is launched from the ground, So = 0 and S(t) = 0

Using s(t)=gt^2+v0t+s0 to get time t

Where g acceleration due to gravity = -4.9m/s^2. and

initial velocity = 39.2 m/a

0 = -4.9t2 + 39.2t

4.9t = 39.2

t = 8s

Substitute t in the model equation

S(t) = -49(8^2) + 3.92(8) + So

Let S(t) =0

0 = - 313.6 + 31.36 + So

So = 282.24m

The equation that can be used to model the height of the rocket after t seconds will be:

S(t) = -4.9t^2 + Vot + 282.24

You might be interested in
Suppose an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that
Deffense [45]

Answer:

The F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.

Step-by-step explanation:

There are four treatments in the data given, i.e. k = 4.

Total number of observations, n = 12.

Note: degrees of freedom is denoted as df.

For treatment, the degrees of freedom = k-1 = 4-1 =3 df.

The total degrees of freedom = n-1 = 12-1 = 11 df.

The error in degrees of freedom = df (total) - df(treatment)

The error in degrees of freedom = 11 - 3 = 8 df

At α = 0.05 level,from the F table, the F-statistic with (3 , 8)df is 4.07.

Therefore, the F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.

8 0
3 years ago
Point L is on line segment
KengaRu [80]

Answer:

k is the option that makes sense

3 0
2 years ago
How many times does seven go into three hundred ninety four
Nookie1986 [14]

Answer: 56 times.

Step-by-step explanation:

394/7 = 56.3

56 * 7 = 392

392 + 7 = 399

399 is more than 394, therefore the answer is 56.

6 0
3 years ago
Read 2 more answers
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
How to know if a triangle is an equalatirral, isoscles, or obtuse?
ikadub [295]
Equilateral: all sides are the same length
isosceles: two sides are the same length
obtuse: there is 1 obtuse angle
4 0
3 years ago
Other questions:
  • If you go to school for 4 hours a day. Every week for a month. What's the total amount of hours you attend school each month ?
    6·2 answers
  • A car travels the 120 miles from A to B at 60 miles per hour, and then returns to A on the same road. If the average rate of the
    8·1 answer
  • Kyle is painting the front door of his house. The dimensions of the door are 80 inches by 36 inches by 2 inches. If he paints al
    5·1 answer
  • Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 3 items in the same time Machine Z p
    6·1 answer
  • What is the median for the given set of data?
    6·2 answers
  • Morgan needed to write an equation.Explain whether she actually wrote an equation 3X5?
    12·1 answer
  • Approximately 1,000,000 people cross the shibuya crossing intersection each day.
    12·1 answer
  • Is the following relation a function? {(1,2), (3,4),(-2,4),(3,0)}
    8·2 answers
  • A pair of sneakers costs $60. Dahlia bought them on sale for $45. What is the percent decrease in the price of the sneakers?
    15·1 answer
  • The area for any square is given by the function ()=2, where x is the length of a side of the square and y is the area of the sq
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!