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dem82 [27]
3 years ago
15

The projectile motion of an object can be modeled using s(t)=gt^2+v0t+s0, where g is the acceleration due to gravity, t is the t

ime in seconds since launch ,s(t) is the height after t seconds,v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is -4.9m/s^2. A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds?
Mathematics
2 answers:
defon3 years ago
8 0

Answer:

the answer is a

Step-by-step explanation:

edge2020

RSB [31]3 years ago
7 0

Answer:

S(t) = -4.9t^2 + Vot + 282.24

Step-by-step explanation:

Since the rocket is launched from the ground, So = 0 and S(t) = 0

Using s(t)=gt^2+v0t+s0 to get time t

Where g acceleration due to gravity = -4.9m/s^2. and

initial velocity = 39.2 m/a

0 = -4.9t2 + 39.2t

4.9t = 39.2

t = 8s

Substitute t in the model equation

S(t) = -49(8^2) + 3.92(8) + So

Let S(t) =0

0 = - 313.6 + 31.36 + So

So = 282.24m

The equation that can be used to model the height of the rocket after t seconds will be:

S(t) = -4.9t^2 + Vot + 282.24

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elena-14-01-66 [18.8K]

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The first statement we have will be

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5 0
2 years ago
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Answer:

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The three angles

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add up to 360∘360∘, as per the question.

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Answer:

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4(x-4)-3x=10

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Hope this helps ^-^

6 0
3 years ago
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