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Ad libitum [116K]
4 years ago
13

Let A = {a, b, d, f, g} and B be a sets in the universe U = {letters of the alphabet}. If A ∩ B = {b, d}, which could be a set o

f B?
(steps to solve problem too please?)

Mathematics
1 answer:
olganol [36]4 years ago
4 0
It is c  because you have to do the work
                              
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kari74 [83]
I can’t read the numbers but when the graph flattens out at the top. There is two points there it’s the first point
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3 years ago
How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?
Serggg [28]

Answer:

45

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

7 0
2 years ago
How would you write 6 × 6 × 6 × 6 as an exponential expression?
lesya692 [45]

Answer:

6⁴ there i hope this helps dude

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
An irrational number between 5/7 and 7/9 is?
Alex17521 [72]

Answer:

Step-by-step explanation:

                                   -----------

5/7 can be written as 0.714285

                                   -----

7/9 can be written as 0.777

∴ An irrational number between 5/7 and 7/9 is 0.72010010001.....

or u ca write other numbers also like

0.73010203.....

0.74090080007.....

7 0
3 years ago
Find the sum of the first 7 terms of the series. 6-12+24-48+...
Mkey [24]

Answer: 258

Step-by-step explanation:

Since, the sum of GP is,

S_{n}=\frac{a(r^n-1)}{r-1}

where r is the common ratio,

a is the first term,

n is the number of term,

Here, series is, 6, -12, 24, -48, _ _ _ _

Which is a GP ( Because there is common ratio in the given consecutive terms )

So, for the above series,  a = 6, r = \frac{6}{-12}=-2  and  n = 7,

⇒ S_{7}=\frac{6(-2^7-1)}{-2-1}

⇒ S_{7}=\frac{6(-128-1)}{-3}

⇒ S_{7}=\frac{6(-129)}{-3}

⇒ S_{7}=\frac{774}{3}=258

Thus, the sum of the 7 terms of the given series is 258.

7 0
3 years ago
Read 2 more answers
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