Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
3bat + 3b² - 6a²t²
Step-by-step explanation:
First you have to expand it to get;
3b(b - at) + 6at(b - at)
Then you can now multiply.
3b² - 3bat + 6bat - 6at²
Group like terms
6bat - 3bat + 3b² -6at²
3bat + 3b² - 6a²t²
Answer:
There are no coefficients.
Step-by-step explanation:
By using simple rule of three, a period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.
<h3>How many terrestrial days are equivalent time in Venus?</h3>
One year on Earth is equivalent to 365.3 days and one year on Venus is equivalent to 224.7 days, the equivalent terrestrial time of 9.5 years on Venus is found by simple rule of three:
x = 9.5 yr × (224.7 days / 1 yr)
x = 2134.65 days
A period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.
To learn more on simple rule of three: brainly.com/question/15209325
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Answer: A
Step-by-step explanation: