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poizon [28]
3 years ago
12

BRAINLIEST ANSWER PLUS EXTRA POINTS! Two planes leaves an airport at the same time, one flying east one flying west. The eastbou

nd plane travels 60 mphslower. They are 3440 mi apart after 4 hr. Find the speed of each plane.
Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

Equation:

distance + distance = 2250 miles

3x + 3(x-110) = 2250

6x - 330 = 2250

6x = 2580

x = 430 mph (rate of the westbound plane)

x-110 = 320 mph (rate of the eastbound plane)


PLS MARK BRAINLIEST!!!

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Help ^^^ use picture above
aalyn [17]
The question reminds you of all the tools you need:

It says ...

"Opposite angles are equal."
So the upper right angle is x+40 just like the bottom left,
and the bottom right angle is 3x+20 just like the upper left.

And it says ...

"The sum of all angles is 360°."
You know what each of the four angles is, so you can addum all up,
set the sum equal to 360, find out what number ' x ' is, and then
use that to find the size of every angle.  

8 0
3 years ago
Read 2 more answers
3+5=8 and 13+5=18 therefore the sum of two odd numbers is an even number
Ratling [72]
True, 13+17=30,51+49=100

3 0
2 years ago
Can someone help pls
RSB [31]

Answer:

<u>In the middle of winter</u>

<u>A farm</u>

Step-by-step explanation:

Setting: The place or type of surroundings where something is positioned or where an event takes place.

6 0
3 years ago
Simplify the expression -(6 - 4p)
Illusion [34]

Hey there!

The answer to your question is -6+4p

Given:

-(6-4p)

First, we distribute the negative sign to both terms (6 and -4p) This would make the 6 negative and the -4p positive, so we have:

-6 and 4p

Add them together and we get:

-6+4p

Have a nice day!

8 0
3 years ago
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
2 years ago
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