- From 3 to 7 is 4
- From 7 to 12 is 5
- From 12 to 18 is 6
- From 18 to 25 is 7
- From 25 to 33 is 8
Continuing the pattern, we can find the next term in the sequence by adding 9 to 33, which gives us 33 + 9 = 42.
To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are .
From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u
Mass Defect =
Thus, the required Mass Defect is
In eV, the Mass Defect is
Well per book there are 4 spots it could be in. So the ratio of books per spots is 1:4, you multiply this by 4 because of four books and her 4:16, making the amount of ways to set them being 16.
The answer is <span>C. y = 4x + 4</span>. You can find the slope by rise over run where the rise is 4 and the run is 1. 4/1 is 4. You also know to add 4 as 4 is the value of y when x=0.
Yes, if you want.
You can multiply 6 times 5 and then multiply 6 times 0.2 :) If you could vote me brainiest that would be awesome!