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oksano4ka [1.4K]
2 years ago
10

5. Using the information from a previous problem and given the tax table, find

Mathematics
1 answer:
Leno4ka [110]2 years ago
3 0

Answer:

Step-by-step explanation:

         ..............................      where is the table

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The population of a local species of dragonfly can be found using an infinite geometric series where a1=42 and the common ratio
san4es73 [151]
\bf \textit{sum of an infinite geometric serie}\\\\
\stackrel{for~~|r|\ \textless \ 1}{S=\sum\limits_{i=0}^{\infty}~a_1r^i\implies \cfrac{a_1}{1-r}}\qquad 
\begin{cases}
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=42\\
r=\frac{3}{4}
\end{cases}
\\\\\\
S=\cfrac{42}{1-\frac{3}{4}}\implies S=\cfrac{42}{\frac{1}{4}}\implies S=164

bearing in mind that, the geometric sequence is "convergent" only when |r|<1, or namely "r" is a fraction between 0 and 1.
3 0
3 years ago
tynya is training a turtle for a turtle race for every 2/3 of an hour that the turtle is crawling he can travel 2/23 of a mile a
Len [333]

Answer:

3/23 miles per hour

Step-by-step explanation:

2 /23 mile

-----------------

2/3 hour

2/ 23 ÷ 2/3

Copy dot flip

2 /23 * 3/2

Rewriting

2/2 * 3/23

3/23 miles per hour

7 0
3 years ago
Read 2 more answers
3. The amount was $120 at 5% rate for 4<br> years.
Inga [223]

Answer:

Go to photo math thank me later

Step-by-step explanation:

dowload tha app on ur phone

5 0
3 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
-4 &lt; - 13( a + 6) -1 7
krek1111 [17]

Answer:

-4 < -13(a+6)-17

-4<-13a+(-78)-17

-4<-13a+(-95)

-4<-13a-95

91<-13a

-91>13a

-7>a

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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