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2 years ago

-5 times h over 50 is equal to -0.1, Solve for h

Mathematics

1 answer:

Vsevolod [243]2 years ago

8 0

Step-by-step explanation:

-5h/50 = -0.1

-1h/10 = -0.1

Multiply both sides by (10/-1)

(10/-1)(-1h/10)= (10/-1)(-0.1)

h= 1

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Evaluate the expression a•b for a =24 and b=8

Butoxors [25]

$\huge\text{Hey there!}$

$\mathsf{a\times b}}$

$\mathsf{= 24\times8}$

$\mathsf{= 192}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{192}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

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1 year ago

This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

BaLLatris [955]

Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

$A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h$

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$

THis is the answer.

6 0

2 years ago

Read 2 more answers

3. Due to leakage, 30% of the water was lost from a water tank. If

Anni [7]

Answer:

1133.3 liters of water after leakage.

Step-by-step explanation:

x*.30=340

x=340/.30

x=1133.33

7 0

2 years ago

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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