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Andrej [43]
3 years ago
11

What is the value of y^2-x^2 when y=6 and x=5

Mathematics
2 answers:
diamong [38]3 years ago
3 0

Answer:

11

Step-by-step explanation:

((6)^2) - ((5)^2) = 11

eduard3 years ago
3 0

Answer:

y= 36 x=25

Step-by-step explanation:

Im not sure if you minus it but if you do it will equal 11

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100/10 = 10 MPH

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8.01 × 10^-2 round the coefficient to two decimal places
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Step-by-step explanation:

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3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

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So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
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