Point P partitions directed line segment AB in the ratio of 3 to 4. If A(-9, -9) and B(5,-2), find the coordinates of point P.

Elza [17]

Factor out a 3x:
3x(x2+4x+6)

Since you can't factor out the quadratic that's as far as it goes:

Answer:
3x(x2+4x+6)

4 0

3 years ago

(39 points PLZ HELP)Find the sum of a finite geometric series. A ball is dropped from a height of 10 meters. Each time it bounce

erastovalidia [21]

So we need to find the sum of the first 5 terms.

You have told me that the first term is 10 meters, and that r = 0.5 per term.

With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).

Plugging in the terms that we know...

s₅=10((1-0.5⁵)/(1-0.5))

s₅=10(0.96875/0.5)

s₅=10(1.9375)

s₅=19.375

With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.

3 0

3 years ago

Read 2 more answers

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

Any equation can be written in function notation<br> O True<br> False

Fynjy0 [20]

Answer: True

Step-by-step explanation:

7 0

2 years ago

A rectangular hotel room is 3 meters by 5 meters. The owner of the hotel wants to re carpet the room with carpet that cost $15.0

eimsori [14]

Answer:

Step-by-step explanation:

The room is rectangular in shape. The formula for determining the area of a rectangle is expressed as

Area = length × width

The rectangular hotel room is 3 meters by 5 meters. The area of the room would be

Area = 3 × 5 = 15 square meters

The owner of the hotel wants to re carpet the room with carpet that cost $15.00 per square meter. This means that the cost to re carpet the room would be

15 × 15 = $225

3 0

3 years ago