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Fittoniya [83]
3 years ago
10

A garden is in the shape of a square with a perimeter of

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

The perimeter of a square is the sum of its sides and they are all equal, so to obtain the length of each of them we divide the perimeter of the first fence between 4:

 P1= 64 feet/4 sides

 P1= 16 feet

 Then, the length of each side of the second fence will increase 2 feet at each end, as shown in the figure. We have then that the perimeter of the second fence is:

 P2 = 20 feet x 4 sides

 P2 = 80 feet

 The sum of the perimeters of both fences is:

 PT = P1 + P2

 PT = 64 feet + 80 feet

 PT = 144 feet

 Total cost = 1.17 $ x 144 feet

 Total cost = 168.48 $

 The total cost of the fences was $ 168.48

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One leg of a right triangle is 7 units long, and its hypotenuse is 16 units long. What is the length of the other leg? Round to
NemiM [27]

Answer:

7^{2} + x^{2} = 16^{2}

49+x^2=256

x^2=207

x=14.387=14

4 0
1 year ago
Felicia opened a bank account and made an openig deposit of $900.
Klio2033 [76]

Answer:

Balance(m) = 900-40m

After 9 months, Felicia has $540.

Step-by-step explanation:

Balance = 900 - 40m

So after 9 months, 900-40*9=900-360=540.

7 0
3 years ago
Where are the points for<br> Y=-x^2+160x-5000
BaLLatris [955]
None are given.  You have to invent your own points that satisfy the given equation.

Examples:  If x = 0, y = -5000   =>  (0,-5000)
                   If x = 2, y = -(2)^2 + 160(2) - 5000 = 4 + 320 - 5000 => (2, -4676)

and so on.  Find as many such points as you want, using the same approach.

4 0
3 years ago
Write an equation in slope-intercept form of the line that passes through the given points
Elis [28]

y= -\frac{3x}{2} +1

3 0
3 years ago
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

7 0
3 years ago
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