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Angelina_Jolie [31]
2 years ago
13

The average person has about 100,000 hairs on their head. However, people with red hair

Mathematics
1 answer:
nirvana33 [79]2 years ago
5 0

Answer:

90,000

Step-by-step explanation:

................

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What is the area of a room that is 3 3/4 yards long and 3 1/3 yards wide
Andreas93 [3]

Answer:

12 1/2 yd^2

Step-by-step explanation:

The area is length times width

A = 3 3/4 * 3 1/3

Change to improper fractions

A = 15/4 * 10/3

Rewriting

A = 15/3 * 10/4

   = 5 * 5/2

   = 25/2

Changing back to a mixed number

   = 12 1/2

6 0
3 years ago
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Does anybody know this?
vagabundo [1.1K]

Answer:

  see attached

Step-by-step explanation:

Reflection in the line y=1 is accomplished by the transformation ...

  (x, y) ⇒ (x, 2 -y)

Each point in the image is as far below the line as the original point is above the line.

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2 years ago
What is the 56th term of the sequence below?<br> -29, -25, -21, -17, . . .
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The 56th term in the sequence is 195
6 0
3 years ago
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There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
If the length of FG is 6 units, what is the length of EH?
QveST [7]

FG goes through the center of the circle, so FG is diameter.

d = 2r \\ r =  \dfrac{d}{2}  \\  \\ r =  \dfrac{6}{2}  = 3

EH=r=3

Answer: EH=3

4 0
3 years ago
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