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3 years ago

Need help will give 14 points

Mathematics

1 answer:

azamat3 years ago

6 0

Answer:

1) False. 2) False.

Step-by-step explanation:

1) False. 2) False.

1) is false because it says, "A total of 40 students can type from 0-59 words per minute." 0-14w=5s, 15-29w=10s, 10-44w=14s, and 45-59w=20s. w= words per minutes s= number of students (BTW) 5+10+14+20=54 not 40

2) is false because it says, "The number of students who typed 45-59 words per minute is equal to the number of students who typed 15-39 and 0-14."

45-59w=20s

15-39w=10s and 0-14w=5s

10s+5s=15s

20s>15s

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I need help with this ?

Alex

Answer:

Joshua worked 4 hours and luke worked 7

Step-by-step explanation:

25x + 35x +105 = 345

60x = 345 - 105

60x = 240

x = 240/60

x = 4 hours

8 0

2 years ago

Translation: 4 units left and 4 units up<br> J(−1, −2), A(−1, 0), N(3, −3)

Molodets [167]

Answer:

(-5,2), (-5,4), and (-1,1)

Step-by-step explanation:

3 0

3 years ago

Help me pls i want to pass my math class

luda_lava [24]

Answer:

Step-by-step explanation:

You know the slope has to be -5, because in the equation it says -5x. You know the y intercept has to be a number on the y axis, and since it says the y intercept is 4 in the equation, you would know its (0,4).

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3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

Pleaseeee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!

Semenov [28]

Answer:

KL = 50

Step-by-step explanation:

∆JML is similar to ∆JNL. it follows that:

[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]

JM = 4 + 20 = 24

JN = 4

JL = 10 + KL

JK = 10

Plug in the values

[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]

[tex] 6 = \frac{10 + KL}{10} [\tex]

Multiply both sides by 10

[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]

[tex] 60 = 10 + KL [\tex]

Subtract 10 from each side

[tex] 60 - 10 = KL [\tex]

[tex] 50 = KL [\tex]

KL = 50

6 0

3 years ago