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3 years ago

i get the concept of slopes and such but i’m not rlly sure how to put a word problem in a graph? can someone please help out?

Mathematics

1 answer:

Setler79 [48]3 years ago

6 0

9514 1404 393

Answer:

see below

Step-by-step explanation:

Read the words down to the point where it says "graph this equation." Then, it's not a word problem anymore—it's a problem of graphing the given equation.

c = 2t +8

The "y-intercept" is the value of "y" when t=0. It is 8. This is the cost of a pizza with 0 toppings.

The slope is the coefficient of t. It is 2. This is the increase in the cost of a pizza when 1 topping is added. The slope is the cost of a topping.

Be aware that the grid on this graph shows squares, but the vertical dimension of the square is $2 while the horizontal dimension is 1 topping. That is, a line with a slope of 2 will lie on the diagonal of a grid square.

_____

Additional comment

We call the point where the graph crosses the vertical axis the "y-intercept." It is called that here, even though "y" is not in the equation or on the graph anywhere. It should rightfully be called the "c-intercept", since the vertical axis shows the value of c, the cost of the pizza.

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(fog)(x) and (gof)(x) f(x)= 8/1-5x g(x)= 1/x Then find the domain for each

Paha777 [63]

To find FoG ( or F of G) you put the equation of G in for the X of F

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Next you can multiply both sides (top and bottom) by x and get the final product.

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3 years ago

You decide to put $175 in a savings account to save for a $3,000 down payment on a new car. If the account has an interest rate

myrzilka [38]

The future value (A) of a principal amount P compounded 12 times per year at rate r for t years is given by
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Substitute the given values and solve for t.
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Taking logarithms, this becomes
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4 years ago

Please help me with this problem. I'm kind of stuck and don't know what to do.

Flauer [41]

Try this option:

1) if csc(u)=9, then 1/sin(u)=9 and sin(u)=1/9;

2) if sin(u)=1/9, then cos(u):

$cos(u)=\sqrt{1-sin^2(u)}=\sqrt{1-\frac{1}{81}}=\frac{4\sqrt{5}}{9};$

3) $if \ sin(u)=\frac{1}{9} \ and \ cos(u)=\frac{4\sqrt{5}}{9}, then$

$sin(2u)=2sin(u)*cos(u)=\frac{8\sqrt{5}}{81};$

$cos(2u)=cos^2(u)-sin^2(u)=\frac{80}{81}-\frac{1}{81}=\frac{79}{81};$

$tan(2u)=\frac{sin(2u)}{cos(2u)}=\frac{\frac{8\sqrt{5}}{81}}{\frac{79}{81} }=\frac{8\sqrt{5}}{79}.$

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2 years ago

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koban [17]

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