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3 years ago

How can you generate x-3y+5 from the expression x+y+4+2y+1

Mathematics

1 answer:

vladimir2022 [97]3 years ago

3 0

Answer: Here is the explanation. also it it +3y not -3y

Step-by-step explanation:

x+y+4+2y+1=x+3y+5 because

2y+y=3y

so now you have x+3y+4+1

4+1=5

now you have: x+3y+5

if you do not understand, What i am trying to say is, you need to add all of the same things.

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3 years ago

Find the three arithmetic means in this sequence. 12 __ __ __ 40

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4 years ago

Mathematics 13 don’t understand

UNO [17]

Answer:

1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)(a^c) = a^(b+c)

Your expression can be simplified as follows:

$\dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}$

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

$(x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6$

Consider division:

$\dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}$

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

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