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3 years ago

10

The distance between two cities on a map is 3.5 centimeters. The map uses a scale in which 1 centimeter represents 20 kilometers

. What is the actual distance between these two cities in kilometers?

1 answer:

mario62 [17]3 years ago

7 0

Answer:

fiarview

6:5=11

330=11 units

divide by 11

30=1 unit

boys=6 unit

30 times 6=180 boys in fiarview

Step-by-step explanation:

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3 years ago

What is the measure of minor arc BD?

Vaselesa [24]

Answer:

$minor\ arc\ BD=100^o$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A <u><em>circumscribed angle</em></u> is the angle made by two intersecting tangent lines to a circle

so

In this problem

BC and CD are tangents to the circle

BC=CD ----> by the Two Tangent Theorem

That means

Triangle ABC and Triangle ADC are congruent

so

$m\angle BAC=m\angle DAC$

Find the measure of angle BAC

In the right triangle ABC

$m\angle BAC+m\angle BCA=90^o$

substitute given value

$m\angle BAC+40^o=90^o$

$m\angle BAC=90^o-40^o=50^o$

Find the measure of angle BAD

$m\angle BAD=2m\angle BAC$

$m\angle BAD=2(50^o)=100^o$

Find the measure of minor arc BD

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3 years ago

Read 2 more answers

Find the angle θ, in radians, in the second quadrant whose tangent is -2.

ololo11 [35]

In order to find the angle θ, in <u>radians</u>, whose<u> tangent</u> is $-2$ you have to follow those steps

Step 1

Using a<u> calculator</u>

Find the angle θ

$Angle=arc\ tan(-2)= -63.43\°$

Remember that

the angle θ belong to the second quadrant

so

Angle θ= $180\°-63.43\°=116.57\°$

Step 2

Convert degrees to <u>radians</u>

we know that

$\pi\ radians=180\°$

$116.57\°=116.57\°*\pi/180\°=0.648\pi\ radians$

therefore

the answer is

the angle θ is $0.648\pi\ radians$

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4 years ago