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OLga [1]
2 years ago
6

If x and y are positive real numbers, which expression is equivalent to the expression below?

Mathematics
1 answer:
Vika [28.1K]2 years ago
8 0

Answer:

<u>The correct answer is C. 21x³y</u>

Step-by-step explanation:

Let's simplify the product, this way:

(49x²y)^1/2 * (27x⁶y^3/2)^1/3

Let's recall that x^1/2 = √x and  x^1/3 = ∛x

√(49x²y) * ∛(27x⁶y^3/2)

7x √y * 3x² √y

Let's recall that √y * √y = √y² = y

21x³y

<u>The correct answer is C. 21x³y</u>

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What is the equation of a line that is parallel to y=5/6x-10 and passes through (12,8)?
Gekata [30.6K]

Answer:

y-8=5/6(x-12)

Step-by-step explanation:

y-y1=m(x-x1)

y-8=5/6(x-12)

8 0
3 years ago
A) Find a polynomial, which, when added to the polynomial 5x2–3x–9, is equivalent to: 18
VMariaS [17]

Answer:

a) -5x^{2}+3x+27

b) -5x^{2}+3x+9

Step-by-step explanation:

a) Let the required polynomial be p(x).

We have the relation, 5x^{2}-3x-9 + p(x) = 18

i.e. p(x) = 18 -5x^{2}+3x+9

i.e. p(x) = -5x^{2}+3x+27


b) Let the required polynomial be q(x).

We have the relation, 5x^{2}-3x-9 + q(x) = 0

i.e. q(x) = 0 -5x^{2}+3x+9

i.e. q(x) = -5x^{2}+3x+9

3 0
3 years ago
Read 2 more answers
What is this hurry please will give brainluest
aleksandr82 [10.1K]

Answer:

450cm²

Step-by-step explanation:

The area of the kite is made up of two pairs of congruent triangles. Find the area of these and add to get the kite's area. (area of triangle = (1/2)(base)height))

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450

3 0
2 years ago
Write an expression using an exponent to represent the
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Answer: 4 to the power of 4

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3 years ago
The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse
diamong [38]

Answer:  The answer is cosine of that acute angle.


Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

Thus, the ratio is cosine of the acute angle.

7 0
2 years ago
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