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Answer:
(a) x^2/16 +y^2/9 = 1
Step-by-step explanation:
The form for the equation of an ellipse centered at the origin is ...
(x/(semi-x-axis))^2 +(y/(semi-y-axis))^2 = 1
The vertex values tell you the semi-x-axis is 4 units, and the semi-y-axis is 3 units. Then you have ...
(x/4)^2 +(y/3)^2 = 1
x^2/16 +y^2/9 = 1
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In case you don't remember that form, you can try any of the points in the equations. The equation that works will quickly become apparent.
Answer:Part A: 13
Step-by-step explanation: look at the graph
Answer:
2πr=72
=2*22/7*r=72
=r=72*7/44=504/44=252/22=126/11=11.45
=πr theta /180=22/7*11.45*60/180
=11.99=12(approx)
answer is (a) 12
Answer:
x = -16
Step-by-step explanation:
2/3 x + 1 = 1/6 x -7
Multiply both sides of the equation by 6 to eliminate the fraction
6*(2/3 x + 1) =6( 1/6 x -7)
4x +6 = x -42
Subtract x from each side
4x-x +6 = -42
3x +6= - 42
Subtract 6 from each side
3x+6-6 = -42-6
3x = -48
3x/3 = -48/3
x = -16
